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OpenStudy (jojokiw3):
Quick question just for verification.
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OpenStudy (jojokiw3):
\[\sin^2-x = \sin^2 x \] Correct?
imqwerty (imqwerty):
sin(-x) = -sin(x) so sin^2(-x)=[-sin(x)]^2 sin^2(-x)=sin^2(x)
OpenStudy (jojokiw3):
...I'm pretty sure it does.
OpenStudy (jojokiw3):
Oh okay. Thought so thanks!
imqwerty (imqwerty):
yea it is the same
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