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Mathematics 21 Online
OpenStudy (jojokiw3):

Quick question just for verification.

OpenStudy (jojokiw3):

\[\sin^2-x = \sin^2 x \] Correct?

imqwerty (imqwerty):

sin(-x) = -sin(x) so sin^2(-x)=[-sin(x)]^2 sin^2(-x)=sin^2(x)

OpenStudy (jojokiw3):

...I'm pretty sure it does.

OpenStudy (jojokiw3):

Oh okay. Thought so thanks!

imqwerty (imqwerty):

yea it is the same

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