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96 / 4^2 * 3^2 + 2^3
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What is the question
The equation above
okay this what i think it is
3*4^(x/2) = 96 4^(x/2) = 32 Recall that a^(bc) = (a^b)^c. Applying this with 4^(x/2), we get: 4^(x/2) = 32 [4^(1/2)]^x = 32 2^x = 32 Then since 32 = 2^5, we get: 2^x = 32 2^x = 2^5 x = 5 I hope this helps!
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