ap calc ab last problem i need help with ! http://prntscr.com/8o5kna

Question

amistre64 · Answer

what did you try?

tmagloire1 · Answer

tmagloire1 · Answer

but the two graphs under those constraints never meet

amistre64 · Answer

youre graph is good, it isnt pieced tho ..

amistre64 · Answer

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tmagloire1 · Answer

how can it be 1 if on the second equation x<0

tmagloire1 · Answer

@amistre64

amistre64 · Answer

-2 <= x <= 0

x > 0

amistre64 · Answer

the graphs touch, they are continuous along -2 to infinity simply becuase they are defined for all real values.

amistre64 · Answer

the top is defined at x=0, the bottom is arbitrarily close to x=0

tmagloire1 · Answer

so we would count 0 as a maximum then?

amistre64 · Answer

when x=0, what is our value of the function?

tmagloire1 · Answer

oops i meant 1!

amistre64 · Answer

at x=0, the max is obtianed, and its value is 1

tmagloire1 · Answer

A bit confused so the max is 0 of my choices, but the value is 1?

amistre64 · Answer

the max is when x=0 ... it is not asking you for the value of x that gets us a max value ... it is asking for the max value itself.

f(0) = 1

tmagloire1 · Answer

ohh ok i didn't ge the whole value part. alright thanks for explaining it!

amistre64 · Answer

good luck