Question

How to find the horizontal and vertical asymptote of the function: \[g(x)=\frac{ 2 }{ x^2+5 }\] using limits?

Answer 1

well... the vertical asymptotes occur when the denominator zeros out
so.... at what values of "x" does the denominator zeros out
that is \(\bf x^2+5=0\implies x=?\)

Answer 2

hmmm ohh.. using limits... hmm so much for the appending there

Answer 3

There's no value of x that'd make the denominator zero.

Answer 4

But I think I figured this one out.

Answer 5

Thanks anyways!