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Exponents question.... Question will be given below
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\[\frac{ -2a^3b^{-2}a^4 }{ (-a^2b^{-1})^2 }\]
okay so here's my work...
\[\frac{ -2a^3b^{-2}a^4 }{ -a^4b^{-2} }\implies \frac{ -2a^7b^{-2} }{ a^4b^{-2} }\implies -2a^{11}\]
Sorry but i have to go eat dinner
can you just check my work and i will look at it asap
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almost, just two small mistakes
first mistake is the denominator (-a^2*b^-1)^2 = a^2*b^-4 the negative sign cancels out, since (-1)^2 = 1
second mistake is a^7/a^4 = a^3, not a^11 (subtract the exponents)
@Vocaloid So would 2a^3 be correct?
almost, -2a^3
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yeah sorry about that.. it was a typo so -2a^3 is correct right?
yes
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