Question

WILL GIVE MEDAL TO BEST ANSWER!!
Factor and show your work
a)8x^2+10x+3
b) 6m^2-3m-3
c)2a^2-11a+12

Answer 1

I'll do the first one and save the other two.

8x^2+10x+3 is of the form ax^2 + bx + c

a = 8
b = 10
c = 3

To get started, look for two numbers that multiply to a*c and add to b.

Multiply to 8*3 = 24 and add to 10.

6 and 4 multiply to 24 and add to 10.

"Bust" the b

8x^2+10x+3

8 x^2 + 6x + 4x + 3 =

2x* ( 4x + 3) + 1*(4x + 3) =

(4x + 3) * ( 2x + 1)

Answer 2

@Directrix i'm not sure if i did part C correctly and i don't know where i might have messed up

Answer 3

2a^2-11a+12
2 X 12=24
8 X 3=24
8+3=11
=2a^2+8a+3a+12
=(2a^2+8a)(3a+12)
=2a(a+4)+3(a+4)
=(a+4)(2a+3)

Answer 4

c) 2a^2-11a+12
----------------
I think there is a sign error but am not sure. Let me look.

Answer 5

Ohhh i think i figured it out...
It's supposed to be -8 X -3 =24
and (-8)+(-3)=11

Answer 6

2a^2-11a+12

2 X 12=24 The two numbers have to multiply to 24 and add to -11

They would be -8 and -3.

Answer 7

okay well for part B, i can't figure out anything else that equals to -18 and adds up to -3
6m^2-3m-3
6 X -3 = -18

Answer 8

It's supposed to be -8 X -3 =24 and (-8)+(-3)= - 11

Correct if you may that negative 11

Answer 9

Before going to that problem, this current problem where
=(a+4)(2a+3) appears is the answer needs correcting.

Answer 10

unless the answer is just -6 and 3

Answer 11

yes, i've already fixed the question on my paper

Answer 12

2a^2-8a-3a+12

2a^2 - 8a -3a + 12

2a(a -4) -3 ( a - 4)

(2a - 3) ( a - 4) -->

Answer 13

part c)
=2a^2-8a-3a+12
=(2a-8a)(-3a+12)
=(2a(a-4)+3(a-4)
=(a-4)(2a-3)

Answer 14

Okay.

Answer 15

now how about for part b?
are the numbers -6 and 3?

Answer 16

b) 6m^2-3m-3

Multiply to -18 and add to -3

Answer 17

-6 x3=-18
-6+3=-3

Answer 18

Oh, first divide through by 3 because that is a common factor.

6m^2-3m-3 = 3*( 2m^2 -m -1)

Focus on this: ( 2m^2 -m -1)

What are two numbers that multiply to -2 and add to -1 ?

Answer 19

-2 X 1=-2
-2 + 1= -1

Answer 20

We will put back the initial 3 after factoring this:

( 2m^2 -m -1)

2 m^2 -2m + 1m - 1 =

2m(m -1) + 1(m - 1) =

(m - 1) (2m +1)

The final answer:

6m^2-3m-3 = 3*(m - 1) (2m +1)

Answer 21

Is that what you got?

Answer 22

yes, i did!
thank you

Answer 23

You are welcome.