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Which equation is the inverse of 5y+4=(x+3)^2+1/2
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please help me
to find inverse `switch x and y` then solve for y variable
\[ \large\rm 5\color{ReD}{y}+4=(\color{blue}{x}+3)^2+ \frac{ 1 }{ 2 }\] inverse would be \[ \large\rm 5\color{blue}{x}+4=(\color{red}{y}+3)^2+ \frac{ 1 }{ 2 }\] now solve 2nd equation for y
can you solve for y?
is it 10?
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@Nnesha
hmm the equation should have the x variable
IS THE ANSWER x=5y^2+10?
show me the steps how did you get ?? and you have to solve for `y` not for x
it's okay if you don't know just let me know so we can work on it together
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