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A worker pushes a 30kg crate 4.5m at a constant, horizontal velocity. The coefficient of kinetic friction between the crate and the floor is 0.25 I have calculated that he has to apply 73.6 N of force and that there is 3.3 J of work done on the crate. Now: How much work is done on the crate by friction and how much by the normal force?
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woops the work is 331 J
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