Question

How much tension must a rope withstand if it is used to accelerate a 1190.0 kg car vertically upward at 0.980 m/s2

Answer 1

on you car are acting two forces:
the weight force: \(W=m \cdot g= 1190 \cdot 9.81=...Newton\)
and the fictitious force: \(F=m \cdot a=1190 \cdot 0.980=... Newtom\)
so total force is \(W+F=...Newton\)