Find the perimeter of a rectangle with l = 0.85 m and w = 0.4 m.
A.
1.25 m
B.
2.5 m
C.
0.34 m
D.
0.68 m
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OpenStudy (anonymous):
@FluffyYumYum
OpenStudy (anonymous):
Any pics?
OpenStudy (anonymous):
nope
OpenStudy (anonymous):
Well just do 0.85+0.4+0.4=?
OpenStudy (anonymous):
xD It's easier with pics
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OpenStudy (anonymous):
0.93
OpenStudy (anonymous):
wait woops
OpenStudy (anonymous):
I was like... Huh?
OpenStudy (anonymous):
3.3
OpenStudy (anonymous):
Nevermind just do one 0.4 because then it adds up to 1.25
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OpenStudy (anonymous):
0.85+0.4=1.25
OpenStudy (anonymous):
And therefor it's A
OpenStudy (anonymous):
xD
OpenStudy (anonymous):
oh well it is right xD
OpenStudy (anonymous):
need any more help?
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OpenStudy (anonymous):
just did all the math lol with a calculator
OpenStudy (anonymous):
yea if I can find some I need help with
OpenStudy (anonymous):
Okay just tag me with it and i'll help you
OpenStudy (anonymous):
k
OpenStudy (anonymous):
Medal? :P
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OpenStudy (anonymous):
Yayyyyy
OpenStudy (anonymous):
lol
OpenStudy (anonymous):
Which equation could be used to find the perimeter of a rectangle that has a width of 18 ft and a length of 24 ft?
A.
P = 18 · 24
B.
P = 2 · 18 + 24
C.
P = 2 · 18 + 2 · 24
D.
P = 16 + 24 @FluffyYumYum
OpenStudy (anonymous):
Okay
OpenStudy (anonymous):
I'd first add 18+24=?
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OpenStudy (anonymous):
32
OpenStudy (anonymous):
42
OpenStudy (anonymous):
stupid computer
OpenStudy (anonymous):
If we did A which is 18*24 that's 432 and thats to big so cross that off
OpenStudy (anonymous):
already done that like 5 billion times to it lol
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OpenStudy (anonymous):
If we do B 2* 18+24= 60. and we already figured out thats its 42 so its to high by just a little bit
OpenStudy (anonymous):
If we do C which is 2* 18+2* 24 we get 84 and thats to high xD
OpenStudy (anonymous):
so its D
OpenStudy (anonymous):
D which is 16+24=40 and thats the closest
OpenStudy (anonymous):
So i'd go with B
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OpenStudy (anonymous):
D*
OpenStudy (anonymous):
lol ok
OpenStudy (anonymous):
xD Stupid fingers
OpenStudy (anonymous):
haha
OpenStudy (anonymous):
2 people want to help me sooo brb I'll tag you there
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