Question

Solve 3x2 + 6x + 15 = 0
−1 ± i
− 1 ± 2i
−2 ± i
−2 ± 2i

Answer 1

@freckles

Answer 2

\(\large\color{black}{ \displaystyle x^2+2x+1=(x+1)^2 }\)

\(\large\color{black}{ \displaystyle 3(x^2+2x+1)=3x^2+6x+9=3(x+1)^2 }\)

*~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~*

\(\large\color{black}{ \displaystyle 3x^2+6x+15=0 }\)
\(\large\color{black}{ \displaystyle 3x^2+6x+9+6=0 }\)
\(\large\color{black}{ \displaystyle 3x^2+6x+9=-6 }\)

\(\large\color{black}{ \displaystyle 3(x+1)^2=-6 }\)
\(\large\color{black}{ \displaystyle (x+1)^2=-2 }\)

Answer 3

and then proceed by taking the square root of both sides and solving for x.

Answer 4

so c?