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Mathematics 24 Online
OpenStudy (horsegal244):

Sry there is a few more...

OpenStudy (horsegal244):

OpenStudy (horsegal244):

@Jadedry

OpenStudy (horsegal244):

@Jadedry

OpenStudy (jadedry):

There are 15 marbles at first, 5 are red. after you pick one red marble, there are 4 reds left in a bag of 14 marbles The two events are dependent so you have to multiply them. = \[\frac{ 5 }{ 15 } * \frac{ 4 }{ 14 }\]

OpenStudy (horsegal244):

ty Here are a few more

OpenStudy (horsegal244):

OpenStudy (jadedry):

@horsegal244 okay

OpenStudy (horsegal244):

You dont need to keep tagging me but ty

OpenStudy (horsegal244):

I think its the second one

OpenStudy (jadedry):

okay, sorry. ;n; so you have a 22/50 chance of getting tails and A 20/50 chance of getting a blue marble, the chance of both happening at the same time is 22/50 * 20/50 = 440/2500

OpenStudy (jadedry):

so yeah, the second one. c:

OpenStudy (horsegal244):

Yay i was right Lol!

OpenStudy (jadedry):

anything else? ;u;

OpenStudy (horsegal244):

OpenStudy (jadedry):

if she replaces the chip then the probability will remain the same, so it is 5/25 * 5/25 = 25/625 because the events are still dependent.

OpenStudy (horsegal244):

Is this correct?

OpenStudy (jadedry):

yes that is correct. c:

OpenStudy (horsegal244):

OpenStudy (jadedry):

there are 36 possibilities. only 2 of those possibilities will give you a total of 11 so you have 2/36 =

OpenStudy (jadedry):

ignore the equal sign at the end, the answer is 2/36

OpenStudy (horsegal244):

18?

OpenStudy (jadedry):

1/18 if you want ti simplify

OpenStudy (horsegal244):

Ok

OpenStudy (jadedry):

unfortunately I need to be off now. :c good luck with your studies. <3

OpenStudy (horsegal244):

I have 2 more questions...

OpenStudy (horsegal244):

OpenStudy (jadedry):

I really can't i'm sorry, it's way late over here. They're both probability right?

OpenStudy (jadedry):

just use the methods I showed you in my solutions, it's the same question with different values.

OpenStudy (horsegal244):

Huh ok...

OpenStudy (jadedry):

Best of luck! c;

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