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Mathematics 13 Online
OpenStudy (anonymous):

Graph ƒ(x) = -1/2x. https://aoa.sooschools.com/media/g_alg01_2015/3/49a.gif https://aoa.sooschools.com/media/g_alg01_2015/3/49c.gif https://aoa.sooschools.com/media/g_alg01_2015/3/35c.gif https://aoa.sooschools.com/media/g_alg01_2015/3/49a.gif Please help me figure this out.

OpenStudy (kva1992):

should be the second one you are given the slop so all you have to do at that point is use that to graph it -1/2 is your slope so rise/run and you should be good after that

OpenStudy (anonymous):

Okay, I believe I understand this now. Thank you. :)

OpenStudy (kva1992):

no problem

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