Question

What is the common ratio of the geometric sequence: 128, -16,2,-1/4

-8

1/8

8

-1/8

Answer 1

: geometric sequence ,to find common ratio \[\large\rm \color{red}{r =\frac{ a_2 }{ a_1} ~~or~~
\frac{ a_4 }{ a_3 }}\] divide any term by previous one
:-)

Answer 2

I got-8 is it right?

Answer 3

no

Answer 4

how did you get -8 ?

Answer 5

I divided 128 by -16

Answer 6

divide any term with the `previous ` one
a_2 = 2nd term over a_1 = first term
divide 2nd term by first one or 3rd term by 2nd one

Answer 7

I don't get that

Answer 8

here is an example
\[4,8,16\] i would divide 8 by 4 to get ratio
not 4 by 8

Answer 9

so the answer is 1/8

Answer 10

well 2nd term is -16 and first one is 128 \[\frac{ -16 }{ 128 }= ??\]

Answer 11

0.125

Answer 12

keep it in fraction focus on sign
negative divide by positive = ?

Answer 13

a negative

Answer 14

right so -16/128 = ?

Answer 15

-1/8

Answer 16

looks good