Question

Find the sine, cosine, and tangent of 45 degrees.

Sin 45 degrees = negative square root of 2 divided by 2, cos 45 degrees = negative square root of 2 divided by 2, tan 45 degrees = negative square root of 2
Sin 45 degrees = square root of 2 divided by 2, cos 45 degrees = square root of 2 divided by 2, tan 45 degrees = square root of 2
Sin 45 degrees = square root of 2 divided by 2, cos 45 degrees = square root of 2 divided by 2, tan 45 degrees = 1
Sin 45 degrees = square root of 2 divided by 2, cos 45 degrees = square root of 2 divided by 2, tan 45 degrees = −1

Answer 1

Remember your special triangles, it can make a problem like this very quick

A 45-45-90 triangle

Answer 2

\[\large sin(\theta) = \frac{opposite}{hypotenuse}\]
\[\large cos(\theta) = \frac{adjacent}{hypotenuse}\]
\[\large tan(\theta) = \frac{opposite}{adjacent}\]

Answer 3

oh now i remember!!! thank you so mcuh!

Answer 4

No problem :)