Question

"find all real solutions" 5x^4+29x^3-x^2+29x-6 = 0


HELP PLEASE PRECAL IS SO HARD!

Answer 1

\(\large\color{black}{ \displaystyle 5x^4+29x^3-x^2+29x-6=\left(5x-1\right)\left(x+6\right)\left(x^2+1\right)}\)

Answer 2

After factoring, you can solve for x by solving three separate cases.

*{1}* \(\large\color{black}{ \displaystyle \left(5x-1\right)=0\\[0.5em] }\)
*{2}* \(\large\color{black}{ \displaystyle \left(x+6\right)=0\\[0.5em]}\)
*{3}* \(\large\color{black}{ \displaystyle \left(x^2+1\right)=0\\[0.5em]}\)

Answer 3

If you are *not* considering any *imaginary* solutions,
then case *{3}* will not have any solutions.