Question

5w^3=4w^2-80w how to solve it

Answer 1

re-write it you have

\[5w^3 -4w^2 + 80w = 0\]

now factor and you get

\[w(5w^2 - 4w + 80) = 0\]

so now you know that 1 solution is w = 0

you can solve the quadratic using the general quadratic formula.

this will result in 2 complex solutions.