Question

What is the equation of the graphed line?

Hint: Determine the slope of the line.

y =
x

Graph of a line passing through the origin and Quadrants II and IV. Line passes through (1, -5).

Answer 1

https://static.k12.com/calms_media/media/1503000_1503500/1503205/3/0539777c91888fdb4df047b53ea5acb32adf5549/MS_IMC-140516-1000015.jpg graph to the question

Answer 2

lets find the slope by using the slope formula and 2 sets of points.
slope(m) = (y2 - y1) / (x2 - x1)
(0,0)...x1 = 0 and y1 = 0
(1,-5)...x2 = 1 and y2 = -5
now we sub
slope(m) = (-5 - 0) / (1 - 0)
slope(m) = -5/1 or just -5

now we use y = mx + b
slope(m) = -5
use either of your points...(1,-5)...x = 1 and y = -5
now we sub and find b, the y intercept
-5 = -5(1) + b
-5 = -5 + b
-5 + 5 = b
0 = b

so the equation of the line is : y = -5x + 0...or just y = -5x