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Mathematics 26 Online
OpenStudy (iwanttogotostanford):

lll

OpenStudy (drummergirl3):

so here is the basics if (x -2) is a factor x = 2 is a zero substitute f(2)=(2)3+7(2)2+14(2)+8 its a positive answer... so not a factor... try (x + 2) which means x - 2 is a zero substitute and check f(−2)=(−2)3+7(−2)2+14(−2)+8 if you evaluate it you'll get f(-2) = 0 so (x + 2) is a binomial factor. hope this makes sense

OpenStudy (drummergirl3):

6x2 - 7x + 2

OpenStudy (anonymous):

sorry, left out the first term

OpenStudy (drummergirl3):

its okay

OpenStudy (triciaal):

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