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Find f(g(-4)) if f(x)=7/(x+2) and g(x)= (x+5)^2 -5/2 -7/2 37/4 7/3
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\[\large\rm \color{royalblue}{f(x)=\frac{7}{x+2}},\qquad\qquad \color{orangered}{g(x)=(x+5)^2}\]
\[\large\rm \color{orangered}{g(-4)=(-4+5)^2}\]\[\large\rm \color{orangered}{g(-4)=?}\]
1?
\[\large\rm \color{orangered}{g(-4)=1}\]Ok good. So then:\[\large\rm \color{royalblue}{f(}\color{orangered}{g(-4)}\color{royalblue}{)}\quad=\quad \color{royalblue}{f(}\color{orangered}{1}\color{royalblue}{)}\]
So the problem boils down to\[\large\rm \color{royalblue}{f(1)=?}\]simply plugging 1 into your f(x) function.
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oh i get it thank u !!
7/3
yay good job \c:/
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