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Can someone please help me find the derivative of this problem? I will fan and medal.
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Whats the function?
I'm typing it
\[\frac{ 2 }{ 3 }\sin^\frac{ 3 }{ 2 }x-\frac{ 2 }{ 7 }\sin^\frac{ 7 }{ 2 }x\]
\[\frac{2}{3}\left(\sin^{2/3}x\right)' \iff \frac{2}{3}\left((\sin(x))^{2/3}\right)'\]
If you look carefully you see that the two functions are connected with the subtract sign. So you can break that function into 2 separate derivatives.
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\[\frac{ d }{ dx } (\frac{ 2 }{ 3 }\sin ^{2/3}(x)) - \frac{ d }{ dx }((\frac{ 2 }{ 7 }\sin ^{7/2}x))\]
Use the power rule, then the chain rule.
|dw:1444350991307:dw|
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