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x^2-8x+7=0
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Whats the question?
What two numbers multiply to give +7 but add to give -8?
-7 -1
I'm pretty sure it's not negative answers tho
so that's why `x^2-8x+7` factors to `(x-7)(x-1)` meaning that `x^2-8x+7=0` is equivalent to `(x-7)(x-1) = 0`
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use the zero product property to solve `(x-7)(x-1) = 0` for x
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