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evaluate the logarithm. log5 (1/25)
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@Jhannybean
\[\large \log_a (x) = \frac{\log_b (x)}{\log_b (a)}\]
@Kainui
(1/25)/5????
close, where are your function denotations?
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what do you mean?
Well I wouldn't use that, I'd use the fact that: \[\log_5(\frac{1}{25}) = \log_5(5^{-2})\] and so log base 5 asks us what exponent is on 5? that exponent is -2, so the answer is -2.
\[\log_5 \left(\frac{1}{25}\right) = \frac{\log\left(\frac{1}{25}\right)}{\log(5)} = \frac{\log(1) -\log(5^2)}{\log(5)}=...\]
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