Question

Find 3 consecutive odd intergers such that 8 times the first integer is 4 more than 20 times the third

Answer 1

Let x be the first of the 3 consecutive odd numbers
The second is x + 2
Third, x + 4

8 times the first integer
8x

20 times the third
20(x + 4)

4 more than 20 times the third
4 + 20(x+4)

Answer 2

8x = 20(x+4) + 4

8x = 20x + 80 + 4 @alli6106 Try your hand at solving for x.