Question

f(x) =(x/8)-3, g(x)=x^3

(f*g)^-1=

Answer 1

is that composite functions?
\[(fog)\]

Answer 2

yes

Answer 3

pretty much substitute g(x) into the x of f(x)

Answer 4

f(g(x))

Answer 5

yeah but i got (x^(1/3)/8)-3

Answer 6

is \[f(x)=\frac{ x }{ 8 }-3\]?

Answer 7

yes

Answer 8

\[(fog)=\frac{ x^3 }{ 8 }-3\]

Answer 9

just plug x ==> x^3

Answer 10

it said it was wrong

Answer 11

@chris00

Answer 12

pic me the question

Answer 13

ohh inverse

Answer 14

\[y=f(x)=\frac{ x }{ 8 }-3\]
y+3=x/8
8y+24=x
then let x=y
8x+24=y=\[f(x)^{-1}\]

Answer 15

so
\[f(x)^{-1}=8x+24\]

Answer 16

do the same for y=x^3

Answer 17

that would be x^1/3

Answer 18

y^(1/3)=x
therefore
\[g(x)^{-1}=x ^{1/3}\]

Answer 19

yep

Answer 20

now\[(fog)^{-1}=8x ^{1/3}+24\]

Answer 21

it says its wrong

Answer 22

lol werid

Answer 23

oh wait

Answer 24

( f o g)–1(x) = (g^–1 o f^ –1)(x)

Answer 25

so we sub f(x) into the x function of g

Answer 26

\[(fog)^{-1}=(8x+24)^{1/3}\]

Answer 27

try that

Answer 28

ah youre amazing!!!! thank you!!!!

Answer 29

:D

Answer 30

just try and know your properties. it a bit confusing
http://www.purplemath.com/modules/fcncomp6.htm
Thats a good link

Answer 31

will do, thanks!

Answer 32

: )