You have a bag containing three red, seven green, and six blue pens. You choose tow pens at random. Find P(blue and blue) with replacing.
Make sure to show/explain your work.
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OpenStudy (anonymous):
so let's see there are 16 pens.
OpenStudy (anonymous):
Choosing blue is 3/8 chance
OpenStudy (anonymous):
second time is 1/3
OpenStudy (anonymous):
multiply to find chance
OpenStudy (welshfella):
first find probability of drawing a blue on a single draw.
since the 2 draws are independent the above probability is multiplied by itself to give the answer you want.
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OpenStudy (anonymous):
The probability of picking two blue pens is approx 12.5%
OpenStudy (1dfanatic):
i got 1/3
OpenStudy (welshfella):
No the probabiluty of a second blue is also 3/8 because the ball is replaced.
OpenStudy (welshfella):
so P(blue and blue) = 3/8 * 3/8
OpenStudy (1dfanatic):
then it'd be 9/64
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OpenStudy (welshfella):
yes
OpenStudy (1dfanatic):
thank you
OpenStudy (welshfella):
you understand why 1 draw = 3/8?
6 out of 16 = 3/8
OpenStudy (welshfella):
yw
OpenStudy (welshfella):
dahmanman would have been right if the ball was not replaced
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OpenStudy (welshfella):
- because there would have been 5 blues out of a total of 15 balls, which = 1/3