Question

Math question

Answer 1

@Michele_Laino

Answer 2

What do you think?

Answer 3

we can rewrite your function as below:
\[f\left( x \right) = \left( {3{x^2}} \right) \cdot x\]
now \(3x^2\) is always positive, for every value of \(x\) (negaitve or positive)
So, what can you conclude?

Answer 4

negative*

Answer 5

are you sure?
if x goes to -infinity, then \(3x^2 \cdot x\) goes to...?

Answer 6

I'm sorry, since if x goes to +infinity, then \(3x^2 \cdot x\) goes to +infinity

Answer 7

correct!

Answer 8

Ah, thank you Michele!

Answer 9

:)