Question

Can you please check my answer?

Describe how to translate the graph of y= sqrt x to obtain the graph of y=sqrt x-9

shift down 9 units
shift left 9 units ****
shift right 9 units
shift up 9 units

Answer 1

@jim_thompson5910

Answer 2

Whats your answer?

Answer 3

shift left 9 units

Answer 4

Oh. Yes. It's shift left 9 unites.

Answer 5

It means its moving across the "x" axis.
The X is horizontal.

Answer 6

So, you're correct :D.

Answer 7

Okay thanks :)

Answer 8

\(\textit{function transformations}
\\ \quad \\

\begin{array}{llll}

\begin{array}{llll} shrink\ or\\ expand\\ by\ {\color{purple}{ A}}\cdot {\color{blue}{ B}}\end{array}
\qquad
\begin{array}{llll} vertical\\ shift\\ by \ {\color{green}{ D}} \end{array}

\begin{array}{llll}{\color{green}{ D}} > 0& Upwards
\\ \quad \\
{\color{green}{ D}} < 0 & Downwards\end{array}
\\

\qquad \downarrow\qquad\qquad\quad\ \downarrow\\
% template start
y = \sqrt{{\color{purple}{ A}} ( {\color{blue}{ B}}x + {\color{red}{ C}} )} + {\color{green}{ D}}\\
% template ends
\qquad\qquad\quad\ \uparrow \\

\qquad\begin{array}{llll} horizontal\\ shift\\ by \ \frac{{\color{red}{ C}}}{{\color{blue}{ B}}}\end{array}

\begin{array}{llll}\frac{{\color{red}{ C}}}{{\color{blue}{ B}}} > 0 & to\ the\ left
\\ \quad \\
\frac{{\color{red}{ C}}}{{\color{blue}{ B}}} < 0& to\ the\ right\end{array}
\end{array}\)