Two six sided dice (one is red, one is green) are rolled. Determined the following probabilities:
1)
What is the probability that the red die is even and the green die is odd? That is, P(R=even∩G=odd)
2)What is the probability that the sum of the red and green values is 8 .
3) What is the probability that the sum of the red and green values is <7 ? That is, P(R+G<7).
4) What is the probability that red value is ≤ green value? That is, P(R≤G)
5) What is the probability that red value ≤ green and the green value is <6 ? That is, P(R≤G∩G<6)
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OpenStudy (anonymous):
1 is .25 do you know why?
OpenStudy (anonymous):
2 is 1/36
OpenStudy (anonymous):
no
OpenStudy (anonymous):
no sorry 7/36
OpenStudy (anonymous):
ok for number 1 do you know that if you have two independent probabilities you multiply them to find their combined probability?
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OpenStudy (anonymous):
so the P(even dice roll)=.5 and P(odd dice roll)=.5 so .5•.5=.25
OpenStudy (anonymous):
there like 2 dice(6*6=36)
OpenStudy (anonymous):
i see, so is 1/4
OpenStudy (anonymous):
\[\frac{ 3 }{ 6 } \times \frac{ 3 }{ 6 }=?\]
OpenStudy (anonymous):
yea
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OpenStudy (anonymous):
that solve the first part, is 1/4
OpenStudy (anonymous):
yea but i would use decimals unless it asks for fractions
OpenStudy (anonymous):
k
OpenStudy (anonymous):
ok so #2
OpenStudy (anonymous):
there are 36 total combinations and only 7 add up to 8
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OpenStudy (anonymous):
so 7/36 would be the probability
OpenStudy (anonymous):
k
OpenStudy (anonymous):
sorry wait i didnt account for 1 so its 8/36 which can be simplified
OpenStudy (anonymous):
1,7 2,6 3,5 4,4 4,4 5,3 6,2 1,7
OpenStudy (anonymous):
those are the combos that add up to 8 for the red and green
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OpenStudy (anonymous):
16/36?
OpenStudy (anonymous):
well no because there are 16 numbers but they come in pairs
OpenStudy (anonymous):
so?
OpenStudy (anonymous):
ya u are right
OpenStudy (anonymous):
{1,7} , so on
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OpenStudy (anonymous):
yea
OpenStudy (anonymous):
ok so #2 is?
OpenStudy (anonymous):
2.
26,35,44,53,62
P=5/36
OpenStudy (anonymous):
^^^^^
OpenStudy (anonymous):
but its 6 not 5 because th 4,4 repeats
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OpenStudy (anonymous):
that solve second question
OpenStudy (anonymous):
yea
OpenStudy (anonymous):
correct.6/36
OpenStudy (anonymous):
so #3 do you know what to do??
OpenStudy (anonymous):
finding a numbers that is less that 7
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OpenStudy (anonymous):
yea but combos like {1,5} so on
OpenStudy (anonymous):
but not =7 its <7
OpenStudy (anonymous):
ya i notice that
OpenStudy (anonymous):
12/36
OpenStudy (anonymous):
try again
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OpenStudy (anonymous):
11,12,13,14,15,21,22,23,24,31,32,33,41,42,51first is G,second is Red
same is first Red,second is Green
P=30/36=5/6