Question

Need help implicit differentiation
Tan(x+y)=x

Answer 1

\[\tan \left( x+y \right)=x\]
diff. w.r.t x
\[\sec ^2\left( x+y \right)\left\{ 1+\frac{ dy }{ dx } \right\}=1\]
\[1+\frac{ dy }{ dx }=\cos ^2\left( x+y \right)\]
\[\frac{ dy }{ dx }=\cos ^2\left( x+y \right)-1=-\sin ^2\left( x+y \right)\]

Answer 2

Thanks ! I need to revisit my trig iD's