Question

Medal & fan
Using a directrix of y = -2 and a focus of (1, 6), what quadratic function is created?

Answer 1

@Nnesha @zepdrix @MeganEdward

Answer 2

or @dan815 or @merchandize lol

Answer 3

;-;

Answer 4

Recall that the vertex of a parabola lies halfway between the focus and the directrix

Answer 5

alright let's pick point (x,y)
we need to find distance between the point (x,y) and focus
and the distance between point and directirx
\[\sqrt{(x - a)^2+(y -b)^2}= \left| y-c \right|\] \[\sqrt{(x- 1)^2 + (y-6)^2} = (y-(-2))^2\]