Question

Could someone please help me solve for the angle

Answer 1

\[64 \cos \theta-64\sin^2\theta+64\cos^2\theta=0\]

Answer 2

\[64(\cos \theta-\sin^2\theta+\cos^2\theta)\]

Answer 3

Double angle identity

Answer 4

got it :)

Answer 5

\(\sin^2 \theta=1-\cos^2\theta\)

Answer 6

oh yea that is more straight forward. thank you