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Solving equation with quadratic formula. Question will be given below
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\[\large 2x^2 - 5x = 52\]
I know that the quadratic formula is: \[\large x = \frac{ -b \pm \sqrt{b^2 - 2ac} }{ 2a }\]
a quadratic equation of the form: ax^2 + bx + c = 0 has roots defined by the quadratic formula as: \[x=\frac{1}{2a}(-b\pm\sqrt{b^2-4ac})\] which is just a shortcut of completing the square
\[\large x = \frac{ -(-5) \pm \sqrt{(-5)^2 - 2(2)(-52)} }{ 2(2) }\] if i solve it like this will it be fine?
@Nnesha @amistre64
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might be a typo, but its 4ac, not 2ac
otherwise your values for abc are good
ok
\[x = \frac{ 5 \pm \sqrt {25 + 208} }{ 4 }\]
if solve it with this will it be correct? @amistre64
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