Question

Can someone please help me with factoring sum of cubes?

Answer 1

part a) is incorrect

Answer 2

hmmmm
you'd be doing the same thing @Directrix alrready suggested
http://openstudy.com/study#/updates/561990efe4b086e96bfef34b

just do an addition of cubes \(\textit{difference of cubes}
\\ \quad \\
a^3+b^3 = (a+b)(a^2-ab+b^2)\qquad
(a+b)(a^2-ab+b^2)= a^3+b^3 \\ \quad \\

a^3-b^3 = (a-b)(a^2+ab+b^2)\qquad
(a-b)(a^2+ab+b^2)= a^3-b^3\)

Answer 3

Jhannybean ahemm, sake of order =)

Answer 4

Oh hahaha Ok \(\checkmark\)

I thought it was to trick my eyes.