2. A candy company places an average of 20 truffles in a one-pound box. The number of truffles per box never varies from the average by more than 2.
Solve the inequality | x - 20 | ≤ 2 . Show all work leading to your answer
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OpenStudy (diana.xl):
@ganeshie8
OpenStudy (diana.xl):
@imqwerty
OpenStudy (anonymous):
Do you know what the modulus signs | ...| mean?
OpenStudy (diana.xl):
absolute value
OpenStudy (anonymous):
Yep good
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OpenStudy (anonymous):
So if i said what values of x has in
|x|=1 what are your solutions
OpenStudy (diana.xl):
If x ≥ 20, this is equivalent to
x - 20 ≤ 2
x ≤ 22
If x < 20, the inequality is equivalent to
20 - x ≤ 2
18 ≤ x
18 ≤ x ≤ 22
OpenStudy (diana.xl):
would that be the way i do it?
OpenStudy (anonymous):
Lets not worry about that. Worry about what i just asked you to do
OpenStudy (anonymous):
So |x|=1
Means that x=+ 1,-1
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OpenStudy (anonymous):
So |x-20| ≤2
Means
x-20 ≤ 2
AND
x-20 ≤-2
OpenStudy (anonymous):
So x ≤22 and x ≤18
So yes 18 ≤x ≤22
OpenStudy (anonymous):
Breaking it down how i have done it is much easier to grasp