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Mathematics 53 Online
OpenStudy (diana.xl):

2. A candy company places an average of 20 truffles in a one-pound box. The number of truffles per box never varies from the average by more than 2. Solve the inequality | x - 20 | ≤ 2 . Show all work leading to your answer

OpenStudy (diana.xl):

@ganeshie8

OpenStudy (diana.xl):

@imqwerty

OpenStudy (anonymous):

Do you know what the modulus signs | ...| mean?

OpenStudy (diana.xl):

absolute value

OpenStudy (anonymous):

Yep good

OpenStudy (anonymous):

So if i said what values of x has in |x|=1 what are your solutions

OpenStudy (diana.xl):

If x ≥ 20, this is equivalent to x - 20 ≤ 2 x ≤ 22 If x < 20, the inequality is equivalent to 20 - x ≤ 2 18 ≤ x 18 ≤ x ≤ 22

OpenStudy (diana.xl):

would that be the way i do it?

OpenStudy (anonymous):

Lets not worry about that. Worry about what i just asked you to do

OpenStudy (anonymous):

So |x|=1 Means that x=+ 1,-1

OpenStudy (anonymous):

So |x-20| ≤2 Means x-20 ≤ 2 AND x-20 ≤-2

OpenStudy (anonymous):

So x ≤22 and x ≤18 So yes 18 ≤x ≤22

OpenStudy (anonymous):

Breaking it down how i have done it is much easier to grasp

OpenStudy (anonymous):

Makes sense?

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