Find the width of rectangle if it's area is (3x^2+9xy+6y^2)
Width is 3x+6y cm
I need help in how to figure this out. I know that area=L*W
And W= Area/length
Unsure how to work this out

Question

Find the width of rectangle if it's area is (3x^2+9xy+6y^2)
Width is 3x+6y cm
I need help in how to figure this out. I know that area=L*W
And W= Area/length
Unsure how to work this out

anonymous · Answer

are there any answer choices?

anonymous · Answer

Unfortunately no

anonymous · Answer

well we know that L*W is area, which is 3x^2+9xy+6y^2. The width is 3x+6y. so L(3x+6x)= 3x^2+9xy+6y^2

anonymous · Answer

whoops I meant 6y*

anonymous · Answer

just divide 3x+6y from both of the sides. It would leave you with x+y. So x+y(3x+6y), distribute the x and y separately, you get 3x^2 +3xy+6xy+6y^2, combine like terms and you get 3x^2+9xy+6y^2

anonymous · Answer

Ok. I think I understand. Thank you

anonymous · Answer

We factored it down as much as possible & got X+y/2  waiting for answer to be graded. Keeping fingers crossed.