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given that log a (4)=2.5 and log a(6)=3.23, what is the value of log a(12)?
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@Directrix
@amistre64
isnt 12 = 6*2?
of 12 = 4*3?
what methods of approach do you know of?
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log(2^2) = 2 log(2) log(6*2) = log(6)+log(2)
well you have to use log 4 and log 6..
only those values
doesnt 4 = 2^2 ?
log(2*2) = log(2) + log(2) = 2 log(2)
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since 2.5 = 2 log(2) we can solve for log(2) and use it to find log(6*2) = log(6)+log(2)
wait I'm confused so what would the answer be...
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