Question

help please ! In the xy. planem the graph of y=x^2 and the circle with center (0,1) and radius 3 hasve now how many points of intersection

Answer 1

x^2+(y-1)^2 = 9
y+y^2-2y-8 = 0
y^2-y-8 = 0
Using the quadratic formula
y = 3.373 (must be positive)
x = 1.837 and -1.837
Intersection at 2 points
(1.837, 3.373) and (-1.837, 3.373)

Answer 2

How I use the quadratic formula in this?