Write the equation of the line that is parallel to the line 4x - 3y = -12 and passes through the point (-3, 4).

Question

anonymous · Answer

ah, first we find the slope of the line 

$$4x - 3y = -12$$

well, lets get it to the form of 

$$y = mx + c $$

so $$4x - 3y = -12$$ add 3y to both sides to get $$4x - 3y + 3y = -12 + 3y$$ which is the same as $$4x = 3y -12$$ and now add 12 to both sides so $$4x +12 = 3y -12 + 12$$ or $$4x + 12 = 3y$$ dividing both sides by three, $$4x/3 + 12/3 = 3y / 3 $$ or $$y = 4/3 + 4$$ 

so we know that m = 4/3 

now you have a line whose slope is 4/3 and it passes through (-3, 4). How do you write an equation for that?