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Discrete Math 22 Online
OpenStudy (anonymous):

I understand the basics but not sure what to do with the S Let A={a,{a},{{a}}} B={⌀,{a},{a,{a}}} C={a} Be subsets of S={⌀,a,{a},{{a}},{a,{a}}}. Find a. A ∩ C b. A’ ∩ B c. (B ∪ C) ∩ A d. {⌀} ∩ B e. ⌀ ∩ B

zepdrix (zepdrix):

S is going to be used in part b) because: \(\large\rm S\setminus A=A'\)

zepdrix (zepdrix):

Any ideas for part a) ? :) All of the elements that show up in A `and` C?

OpenStudy (anonymous):

{a,{a},{{a}}} u {a}

OpenStudy (anonymous):

yeah i guess i dont get this

zepdrix (zepdrix):

you mean {a,{a},{{a}}} `n` {a} ? :o

OpenStudy (anonymous):

yeah sorry

zepdrix (zepdrix):

\[\large\rm A\cap C \quad=\quad \{~\color{orangered}{a},\{a\},\{\{a\}\}~\} \quad\cap\quad \{\color{orangered}{a}\}\]

zepdrix (zepdrix):

See what they have in common? :)

zepdrix (zepdrix):

No, you're thinking union :O Take stuff from either of the sets and combine it all together.

zepdrix (zepdrix):

But also, keep in mind that we don't repeat elements, even when doing union,\[\large\rm \{a,b\}\cup \{a\}\ne \{a,a,b\}\]\[\large\rm \{a,b\}\cup \{a\}= \{a,b\}\]

zepdrix (zepdrix):

If I draw it visually maybe it'll help.

OpenStudy (anonymous):

ok thank you

zepdrix (zepdrix):

|dw:1444809228675:dw|

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