Question

*Fan & medal*
What do I do for this...? Please explain, as I have a ton of them I need to do.

Answer 1

for each "iteration" you take the output value of the function and input it into the function again

Answer 2

so, since f(1) = 2, then for the next iteration f2(1), you put 2 into the function, and double it to get 4

Answer 3

obviously, as the number of iterations increases, the output value keeps doubling. you can verify this by performing the 10 iterations yourself

Answer 4

So the next one would be f^4(1) = 2 * 2 * 2 * 2 * 1 = 16?

Answer 5

yeah

Answer 6

Okay, so I just do that 10 times?

Answer 7

I presume so, you can stop at f10

Answer 8

Okay thanks, and for the second part I just do the same, but negative?

Answer 9

yes

Answer 10

Okay thanks! :D

Answer 11

Okay, so just like this for part 1?
f^4(1) = 2 * 2 * 2 * 2 * 1 = 16
f^5(1) = 2 * 2 * 2 * 2 * 2 * 1 = 32
f^6(1) = 2 * 2 * 2 * 2 * 2 * 2 * 1 = 64
f^7(1) = 2 * 2 * 2 * 2 * 2 * 2 * 2 * 1 = 128
f^8(1) = 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2 * 1 = 256
f^9(1) = 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2 * 1 = 512
f^10(1) = 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2 * 1 = 1024

Answer 12

yeah