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Separate 846 into 3 parts so that the second part is twice the first part and the third part is triple the second part. Which of the following equations could be used to solve the problem? 846 = x + 2x + 3x 846 = x + 2x + 6x 846 ÷ 3 = x + 2x + 6x
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first part=x second part=twice the first=2x third part=triple the second=3*2x=6x
sum of three parts=846
anything else to explain just in case? and thank you
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