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Precalculus
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Write the first trigonometric function in terms of the second for θ in the given quadrant. sec θ, tan θ, θ in quadrant II
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don't forget this identity \[\huge\rm \sin^2\theta +\cos^2 \theta=1\]
sec x =1/cosx tanx = sinx/cosx cot= cosx /sin x csc x= 1/sinx sec ,csc cot AND 1/sin ,1/cos,1/ tan are reciprocal of each other
to find sec theta first solve that identity for cos theta
\[\huge\rm \sin^2\theta +\cos^2 \theta=1\] cos theta = ?
|dw:1444876430367:dw| remember the CAST rule for signs
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