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Mathematics 10 Online
OpenStudy (ayee_ciera):

WILL FAN AND MEDAL PLS HELP

OpenStudy (ayee_ciera):

what are the solutions to the quadratic equation of \[2x ^{^{2}}-16x+32=0\]and how would i solve this?

OpenStudy (dayakar):

\[2x^{2}-8x-8x+32\]=0

OpenStudy (dayakar):

2x(x-4)-8(x-4)=0

OpenStudy (dayakar):

(x-4)(2x-8)=0

OpenStudy (dayakar):

x-4=0 or 2x-8 =0 x=4 or x=8/2 =4 x=4 that means equal roots

OpenStudy (dayakar):

are u following

OpenStudy (ayee_ciera):

yes @dayakar

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