Derive the equation of the parabola with a focus at (−5, 5) and a directrix of y = −1.

f(x) = −one twelfth (x − 5)^2 + 2
f(x) = one twelfth (x − 5)^2 + 2
f(x) = −one twelfth (x + 5)^2 + 2
f(x) = one twelfth (x + 5)^2 + 2

Question

Derive the equation of the parabola with a focus at (−5, 5) and a directrix of y = −1.

 f(x) = −one twelfth (x − 5)^2 + 2
 f(x) = one twelfth (x − 5)^2 + 2
 f(x) = −one twelfth (x + 5)^2 + 2
 f(x) = one twelfth (x + 5)^2 + 2

gabylovesyou · Answer

@phi

gabylovesyou · Answer

@ParthKohli

kendricklamar2014 · Answer

http://openstudy.com/study#/updates/54c0721ae4b0d372e15bd7e5

kendricklamar2014 · Answer

This user asked the same question, and got a detailed explanation and answer from @Miracrown