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Mathematics 20 Online
OpenStudy (racelynn):

Starting from 111 feet away, a jogger runs towards a checkpoint and then passes it. The jogger is running at a constant rate of 1.5 feet per second. The distance between the jogger and checkpoint is given by the equation d = |111 – 1.5t|. At what time is the jogger 50 feet from the checkpoint?

OpenStudy (anonymous):

33.33 maybe? :)

OpenStudy (racelynn):

Thank you :)

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