What is the equation of the quadratic graph with a focus of (5, 6) and a directrix of y = 2?

f(x) = one eighth (x + 5)^2 + 4
f(x) = −one eighth (x − 5)^2 + 4
f(x) = one eighth (x − 5)^2 + 4
f(x) = one eighth (x + 5)^2 − 4

Question

What is the equation of the quadratic graph with a focus of (5, 6) and a directrix of y = 2?

 f(x) = one eighth (x + 5)^2 + 4
 f(x) = −one eighth (x − 5)^2 + 4
 f(x) = one eighth (x − 5)^2 + 4
 f(x) = one eighth (x + 5)^2 − 4

gabylovesyou · Answer

@mathmath333 @undeadknight26 @dan815

gabylovesyou · Answer

@freckles

freckles · Answer

the vertex is halfway between the focus and the directrix
I like to look at a visual...
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