Question

what is the solution to the linear-quadratic system of equation
y=x^2+5x-3
y-x=2

Answer 1

y = x^2 + 5x - 3
y - x = 2

set y - x = 2 equal to x, so x = 2-y.

Then plug in x = 2 - y for the other equation such that:

y = (2-y)^2 + 5(2-y) - 3

Then solve for y

Answer 2

@zkoqmosii i got y=11-4y is that correct?