Question

You are designing a marble basin that will hold a fountain at the center of a zoo. The basin's slides and bottom should be 1 foot thick. Its outer length should be twice its outer width and outer height. What should the outer dimensions of the basin be if it is to hold 36 cubic feet of water?

Answer 1

are there any options???

Answer 2

no

Answer 3

ok i know this has nothing to do with your question But your name is really familiar. ok do you know anything about JIS?

Answer 4

No, is that a name or something?

Answer 5

let the length of the inner part be x
then outer length = x + 2
outer width will be 0.5(x + 2)
outer height = 0.5(x + 2)

inner width = 0.5(x + 2) - 2 = 0.5x - 1
inner height = 0.5(x + 2) - 1 = 0.5x

Answer 6

Nope. theres was a girl in my class in JIS and she had the same name Lol

Answer 7

so inner volume = x(0.5x)(0.5x - 1) = 36

solve for x

Answer 8

@Welshfella is right. :)

Answer 9

only problem is you have a cubic equation . Maybe there's an easier way...

Answer 10

that one simplifies to

0.25x^3 - 0.5x^2 - 36 = 0

Answer 11

you can either solve this by trial and improvement or graphically or using a graphical calculator ( thats the easiest way - lol!!)

Answer 12

would the answer be 4?

Answer 13

i'll check my calc

i get x to be 5.369 m

Answer 14

Okay, thank you.

Answer 15

oops sorry I made an error !!

Answer 16

;x comes to exactly 6

Answer 17

that is the internal length
but the question asks for the outer dimensions

so
outer length = 6 + 2 = 8
outer width = 0.5 * 8 = 4
and outer height = = 4