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Mathematics 14 Online
OpenStudy (vera_ewing):

Pre-calculus question

OpenStudy (vera_ewing):

OpenStudy (vera_ewing):

A.

OpenStudy (vera_ewing):

B.

OpenStudy (vera_ewing):

C.

OpenStudy (vera_ewing):

D.

OpenStudy (vera_ewing):

Can you explain why it's not A or C please?

Parth (parthkohli):

Because it's not a straight line.

Parth (parthkohli):

You get a horizontal asymptote when something isn't included in your range. To find what isn't included in the range, do this:\[y = \frac{5x - 2}{x+2}\]\[yx + 2y = 5x - 2 \]\[(y-5)x = -2 - 2y\]\[x = \frac{-2-2y}{y-5}\]Obviously, \(y=5\) wouldn't be included in the range.

OpenStudy (anonymous):

is the answer D.

Parth (parthkohli):

Nah.

OpenStudy (anonymous):

is it b

OpenStudy (vera_ewing):

Thank you, Parth.

Nnesha (nnesha):

or if the highest degree of the numerator and the highest degree of the denominator are the same so you can just divide leading coefficients \[\frac{ 5x^{\color{ReD}{1}}-2 }{ x^\color{ReD}{1}+2 }\] to find horizontal asy y =5/1 =5

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