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Pre-calculus question
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A.
B.
C.
D.
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Can you explain why it's not A or C please?
Because it's not a straight line.
You get a horizontal asymptote when something isn't included in your range. To find what isn't included in the range, do this:\[y = \frac{5x - 2}{x+2}\]\[yx + 2y = 5x - 2 \]\[(y-5)x = -2 - 2y\]\[x = \frac{-2-2y}{y-5}\]Obviously, \(y=5\) wouldn't be included in the range.
is the answer D.
Nah.
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is it b
Thank you, Parth.
or if the highest degree of the numerator and the highest degree of the denominator are the same so you can just divide leading coefficients \[\frac{ 5x^{\color{ReD}{1}}-2 }{ x^\color{ReD}{1}+2 }\] to find horizontal asy y =5/1 =5
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